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A non conduction ring of raducs R Has u...

A non conduction ring of raducs R Has uniformly distributed positive charge ` Q.A` small part of the ring of length d, is removed (d lt lt R) . The electric field at the centre of the ring now be .

A

directed towards the gop,inversl propprtional to `R^(3)`

B

directed towards the gap, inversly proportional to ` R^@`

C

directed away from the gap, inversly

D

directed away from the gap, inversly proportional to ` R^@`

Text Solution

Verified by Experts

The correct Answer is:
A
Field due to charged arc at the centre of arc
` E = (2 K lambda)/R . Sin (theta)/2`

Field due to remaining part at the centre will be equal and opposite to the field due to removed part .
` (##NG_PHY_C01_E01_008_S02.png" width="80%">
`E = (2 k lambda)/R . sin (theta)/2` For small ` theta`
` E = (K lambda) /R theta = K/R . Q/(2 pi R) . d/R`
` E = (KQd)/(2piR^3)`.
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