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Two equal negative charges -q are fixed ...

Two equal negative charges `-q` are fixed at points `(0, -a)` and `(0,a)` on y-axis. A poistive charge Q is released from rest at point `(2a, 0)` on the x-axis. The charge Q will

A

execute simple harmonic motion about the origine

B

move to the origin and remain at rest

C

move to infinity

D

execute oscillatory but not simple harmonic motion.

Text Solution

Verified by Experts

The correct Answer is:
D
` F_R =- 2F cos theta`
` F_R =- 2 (KQq.xa)/((x^2 +a^2)^(3//2))`
Since ` x gt gt a`, so particel
` (##NG_PHY_C01_E01_010_S01.png" width="80%">
will excute oscillatory motion.
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