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Two identical thin ring, each of radius ...

Two identical thin ring, each of radius R meters, are coaxially placed a distance R metres apart. If `Q_1` coulomb, and `Q_2` coulomb, are repectively the charges uniformly spread on the two rings, the work done in moving a charge q from the centre of one ring to that of the other is

A

zero

B

` q(Q_1-Q_2) (sqrt2-1)//(sqrt2.4pi varepsilon_0 R)`

C

`qsqrt 2 9Q_1 +q_2 )//4 pi varepsilon_0 R_)`

D

` q (Q_1 -Q_2) (sqrt 2+1) //(sqrt2.4 pi varepsilon_2R)`

Text Solution

Verified by Experts

The correct Answer is:
B

` V_A = (KQ_1)/R + (KQ_2)/(sqrt 2R)` and

` V_B = (KQ_2)/R + (KQ_1)/(sqrt 2R)`
`W+_(AB) =q (V_(B) -V_(B))q(K)/(R)[ Q_(2) (1 -(1)/(sqrt2))-Q_(2) (1-(1)/(sqrt2))]`
`W_(AB) =(q)/(4pi in_(0)R) ((sqrt2-1))/(sqrt2) (Q-Q_(2))=(q(Q_(2)-Q_(1))(sqrt2-1))/(sqrt24piin_(0)R)`
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