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An ellipsoidal cavity is carved within a...

An ellipsoidal cavity is carved within a perfect conductor. A positive charge q is placed at the centre of the cavity. The points A and B are on the cavity surface as shown in the figure. Then

A

electric field near A in the cavity = electiric field near B in the cavity

B

charge density at A = charge density at B

C

potential at A= potential at B

D

total etectric feled flux through the surface of the cauity is ` q // varepsilon_0`

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The correct Answer is:
C
Since point `A and `B` are lying on conducto so they will have equal potential .
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