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A particel of charge 1 mu C & mass 1 m...

A particel of charge ` 1 mu C & ` mass `1 mg` moving with a velocity of ` 4 m//s` is subjected to a unifrm electric field of magnitude ` 300 V m` for ` 10 sece`. Then it s final speed cannot be :

A

` 0. 5 m//s`

B

` 5 m//s`

C

` 3 m//s`

D

` 6 m//s`

Text Solution

Verified by Experts

The correct Answer is:
A, B, C
`a= (qE)/m = 0. 3 m//s^2 rArr at = 3 m//s^2`
` vec V = vec x + vec at`
From vector addition
`(x-at ) le V le u + a t`.
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