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A dipole is placed at origin of corrdina...

A dipole is placed at origin of corrdinate system as shown in figure, find the electric field at point ` P (0, y)`
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Text Solution

Verified by Experts

The correct Answer is:
` (kP) /( sqrt 2 y^3) ( - hat I - 2 hat j)`
` E_1` fild intensity at `P` due to p cos `theta`
`E_2 =` Field intensity at `P` due to `P sin theta`
`vec E_1 = (KP cos theta )/y^3 ( - hat j)`
` (##NG_PHY_C01_E01_114_S01.png" width="80%">
`vec E _p = vec E_1 = vec E_2 = (KP cos theta)/(y^3) (- hat i) + ( 2 KP sin theta)/y^2 (- hat j)`
By putting `theta = 45^@, vec E_p = (KP)/(sqrt 2 y^3) (- hat i - 2hat j)`.
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