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A positive charge q is placed in front o...

A positive charge q is placed in front of conducting solid cube at a distance d from its centre. Find the electric field at the centre of the cube due to the charges appearing on its surface.

Text Solution

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The correct Answer is:
` q/ (4 pi varepsilon_0d^2)` towards the charge (q)
`vec E_q + vec E_("induced") =0 rArr vec E_("induced") =- vec e_q`
`vec E_("induced") = q/(4 pi in_0 d^2)` tiwards charge `q`.
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