Home
Class 12
PHYSICS
A charge +Q is fixed at the origin of th...

A charge `+Q` is fixed at the origin of the co-ordinate system while a small electric dipole of dipolement `vecp` pointing away from the charge along the x-axis is set free from a point far away from the origin.
(a) Calculate the K.E. of the dipole when it reaches to a point (d, 0).
(b) Calculate the force on the charge `+Q` at this moment.

Text Solution

Verified by Experts

The correct Answer is:
(a), `K.E. = ( P)/(4 pi varepsilon_0 d^2) (b) (QP)/(4 pi varepsilon_0 d^3)` along positive x -axis.
(a) `U_i =0`
`U_r =- PE cos 0^@ =- (KQP)/d^@`

From energy conservation
Gain of `K. E=` Loss of `PE.`
`K_r - K_i =U_i -U_r rArr K_r -0 =0 - ( - (KQP)/(d^@))`
`rArr K_f = (KQP)/(d^@) = 1/(4 pi in_0) (QP)/(d^2)`
(b) `F=-0 (dU)/(dr) rArr F =- 2 (KQP)/(d^2) rArr F`
`=- 1/(2 pi in_0) (QP)/(d_3)` .
Promotional Banner

Similar Questions

Explore conceptually related problems

A positive charge q is fixed at the origin. An electric dipole withe dipole moment vecP is placed ,.iong th ex-axis faraway from the origin with vecP pointing along thepositivex-axis and it is set free to move. The kinetic energy .when it reaches a distance x from the origin is Kand the magnitude of the force experienced by charge q at this moment is F. Then :

A positive charge is fixed at the origin of coordinates. An electri dipole which is free to move and rotate is placed on the positive x -axis. Its moment is directed away from the origin. The dipole will

A positive point charge q is fixed at origin. A dipole with a dipole momen vec(p) is placed along the x-axis for away from the orgin with vec(p) poiniting along positive x-axis . (i) If the kinetic energy of the diople when it reachers a distance d from the origin is ( qp)/( 4 pi epsi_(0) d^(n)) , then n is . (ii) If the force experienced by the charge q at this moment is (4qp)/(pi epsi_(0) d^(3)), hat(i) then x is.

An electric dipole is placed at the origin O and is directed along the x -axis. At a point P , far away from the dipole, the electric field is parallel to y -axis. OP makes an angle theta with the x -axis then

A short electric dipole has dipole moment p. Find the distance of farthest point from the dipole where (a) potential due to the dipole is V_0 (b) Electric field due to the dipole is E_0

Calculate the magnitude of the force, due to an electric dipole of dipole moment 3.6xx10^(-29) C-m , on an electric 25mm from the center of the dipole , along the dipole axis. Assume that this distance is large relative to the dipole's charge separation.

A point charge q is placed at the origin . How does the electric field due to the charge very with distance r from the origin ?

A small electric dipole is placed at origin with its dipole moment directed along positive x-axis .The direction of electric field at point (2,2sqrt(2),0)

A small electric dipole is placed at origin with its dipole moment directed along positive x-axis. The direction of electric field at point (2, 2sqrt(2), 0) is

What is the magnetic induction due to a short magnetic dipole of moment 0.1 Am^(2) at an equatorial point 10 cm away from the centre of the dipole/