Home
Class 12
PHYSICS
Two identical capacitors 1 and 2 are con...

Two identical capacitors `1` and `2` are connected in series to a batery as shown in figure. Capacitor `2` contains a dielectric slab of dieletric constant `k` as shown. `Q_(1)` and `Q_(2)` are the charges stored in the capacitors. Now the dielectirc slab us removed and the corresponding charges are `Q'_(1)` and `Q'_(2)`. Then

A

`(Q'_(1))/(Q_(1))(k +1)/(k)`

B

`(Q'_(2))/(Q_(2))=(k+1)/(2)`

C

`(Q'_(2))/(Q_(2)) =(k+1)/(2k)`

D

`(Q'_(1))/(Q_(1)) =(k)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`Q_(1)=Q_(2) = (KCM)/(K+1)`
when dielectric slab is removed
`Q'_(1) = Q'_(2) = (CE)/(2) rArr (Q'_(2))/(Q_(2)) = (K+1)/(2K)`
Promotional Banner

Similar Questions

Explore conceptually related problems

Two capacitors C_(1) and C_(2) are connected to a battery of 6 V as shown in Fig. Find the charge on each capacitor.

Two identical parallel plate capacitors are connected in series to a battery of 100V . A dielectric slab of dielectric constant 4.0 is inserted between the plates of second capacitor. The potential difference across the capacitors will now be respectively

Two identical capacitor C_(1) and C_(2) are connected in series with a battery. They are fully charged. Now a dielectric slab is inserted between the plates of C_(2) . The potential across C_(1) will :

Two identical capacitors are connected as shown in the following figure. If a dielectric slab is inserted in B, choose correct statement

Two identical capacitors A and B shown in the given circuit are joined in series with a battery. If a dielectric slab of dielectric constant K is slipped between the plates of capacitor B and battery remains connected, then the energy of capacitor A will-

Two identical capacitors are connected in series with a source of constant voltage V . If Q is the charge on one of the capacitors, the capacitance of each capacitor is :

A capacitor is connected to a battery of voltage V. Now a di-electric slab of di-electric constant k is completely inserted between the plates, then the final charge on the capacitor will be : (If initial charge is q_(0) )

Two cellls, two resistance and two capacitors are connected as shown in figure. The charge on 2muF capacitors is

Two identical parallel plate capacitors are connected in series and then joined in series will a batter of 100 V . A slab of dielectric constant K=3 is inserted between the plates of the first capacitor. Then, the potential difference across the capacitor will be, respectively.

Space between plates of a capacitor (of area A ) is filled two dielectric slab of dielectric constant k_(1) and k_(2) .The capacitor is connected to battery of emf E then the charge stored on the capacitor will be (d_(2)=1.5d_(1) and k_(1)=2k_(2))