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If Q is the charge on the pates of a cap...

If `Q` is the charge on the pates of a capacitor of capacitances `C,V` the potential difference between the plates, `s` the area of each plate and `d` the distance between the plates, the force of attraction between the plates is-

A

`(1)/(2)((Q^(2))/(epsilon_(0)A))`

B

`(1)/(2)((CV^(2))/(d))`

C

`(1)/(2)((CV^(2))/(Aepsilon_(0)))`

D

`(1)/(4)((Q^(2))/(piepsilon_(0)d^(2)))`

Text Solution

Verified by Experts

The correct Answer is:
A, B
`F_(B) = Q((sigma)/(2 in_(0))) = (Q^(2))/(2 in_(0)A)`
`F_(B) = (Q^(2))/(2 in_(0)A) (Q^(2))/((2 in_(0)A)/(d)xxd) =(Q^(2))/(2Cxxd) = (1)/(2)(CV^(2))/(d)`
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