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In the circuit shown in figure C(1) =C(2...

In the circuit shown in figure `C_(1) =C_(2) = 2muF`. Then charge stored in

A

capacitor `C_(1)` is zero

B

capacitor `C_(2)` is zero

C

both capacitor is zero

D

capacitor `C_(1)` is `40muC`

Text Solution

Verified by Experts

The correct Answer is:
B, D

(B) Charge on capacitor `C_(2)` is zero because there is no potential difference.
(C ) Charge on capacitor `C_(1) = 2muF xx 20V = 40muC`
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