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STATEMENT-1: A parallel plate capacitor ...

STATEMENT-1: A parallel plate capacitor is charged by a battery of voltage `V`. The battery is then disconnected. If the space between the plates is filled with a dielectric, the enegry stroed in the capacitor will decrease
STATEMENT-2: The capacitance of a capacitor increases due to the introduciton of a dielectric between the plates.

A

Statement -1 si Ture, Statement -2 is True, Statement -2 is a correct explanation for Statement -1.

B

Statement-1 is True, Statement-2 is True, Statement-2 is Not a correct explanation for Statement-1.

C

Statement-1 is True, Statement-2 is False.

D

Statement-1 is False, Statement-2 is True.

Text Solution

Verified by Experts

The correct Answer is:
B
The correct choice is `(B)`. The charge `Q` on the capacitor plates remains uncharged because there is no source to supply extra charge as the battery is disconnected. The capacitance `C` increases due to the introduction of the dielectric. Now, enegry stored `U = Q^(2)//2C`. Since `Q` remain uncharged and `C` increases, `U` will decreases.
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