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One end of a Nichrome wire of length 2L ...

One end of a Nichrome wire of length `2L` and cross-sectional area `A` is attatched to an end of another Nichrome wire of length `L` and cross-sectional area `2A`. If the free end of the longer wire is at an electric potential of `8.0` volts, and the free end of the shorter wire is at an electric potential `1.0` volts, the potential at the junction of the two wires is equal to

A

`2.4 V`

B

`3.2V`

C

`4.5V`

D

`5.6 V`

Text Solution

Verified by Experts

The correct Answer is:
A

`R=(rho2L)/A…(1)`
`R'=(rhoL)/(2A)…(2)`
From `(1)` and `(2)` `R=4R'`
drop along `2L, =4/5xx(8-1)=5.6`
So, `V_(J)=8-5.6 =2.4 V`
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