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In the figure shown the total power gene...

In the figure shown the total power generated is

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The correct Answer is:
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`P=I^(2)y=(10/(2+y+R))^(2)Y=100/((2+y+R)^(2)) y`
For `P` to be maximum
`(dP)/(dy)=0 implies d/(dy)(100y)/((2+y+R)^(2))=0`
`R=y-z` put `y=5implies R=3 Omega`
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