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In the box shown current i enters at H a...

In the box shown current `i` enters at `H` and leaves at `C`. If `i_(AB) = i/6, i_(DC) = (2i)/3 , i_(HA) = i/2 , i_(GF)= i/6 , i_(HE) = i/6 `, choose the branch in which current is zero

A

`BG`

B

`FC`

C

`ED`

D

none

Text Solution

Verified by Experts

The correct Answer is:
B

Applying junction law at `H`
`I_(HG)=i-(i/2+i/6)=i/3`
Applying junction law at `G`
`I_(HG)=i/6+I_(GB) impliesI_(GB)=i/6`
Applying junction law at `B`
`I_(BC)=I_(GB)+i/6=i/3`
Applying junction law at `C`
`I_(BC)+(2i)/3+I_(FC)=iimpliesI_(FC)=0`
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