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A galvanometer has a resistance of 20Ome...

A galvanometer has a resistance of `20Omega` and reads full-scale when `0.2V` is applied across it. To convert it into a `10A` ammeter, the galvanometer coil should have a

A

`0.01 Omega` resistor connected across it

B

`0.02 Omega` resistor connected across it

C

`200 Omega` resistor connected in series with it

D

`2000 Omega` resistor connected in series with it

Text Solution

Verified by Experts

The correct Answer is:
B

`I_(g)=0.2/20=0.01` amp
`(I-I_(g))S=I_(g)xxG`
`S=(I_(g).G)/(I-I_(g))impliesS=G/((I/(I_(g))-1))`
`S=20/(10/0.01-1)=20/999=0.02 Omega`
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