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A galvanometer coil has a resistance 90 ...

A galvanometer coil has a resistance `90 Omega` and full scale deflection current `10 mA`. A `910 Omega` resistance is connected in series with the galvanometer to make a voltmeter. If the least count of the voltmeter is `0.1 V` the number of divisions on its scale is

A

`90`

B

`91`

C

`100`

D

none

Text Solution

Verified by Experts

The correct Answer is:
C
`I_(g)(R+G)=VimpliesR+G=V/I_(B)`
`R=V/(I_(g))-G`

`V=(R+G)I_(g)=(910+90)xx10mA=10`volt
`Nxx0.1=10 implies N=100`
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