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In the figure shown for given values of ...

In the figure shown for given values of `R_1` and `R_2` the balance point for Jockey is at `40cm` from `A`. When `R_2` is shunted by a resistance of `10Omega`, balance shifts to `50cm`. `R_1` and `R_2` are (`AB=1cm`):

A

`10/3 Omega,5 Omega`

B

`20 Omega,30 Omega`

C

`10 Omega,15 Omega`

D

`5 Omega,15/2 Omega`

Text Solution

Verified by Experts

The correct Answer is:
A
`(R_(1))/(R_(2))=40/60implies(R_(1))/(R_(2))=2/3….(1)`
`(R_(1))/(10R_(2)//(R_(2)+10))=50/50 = impliesR_(1)=(10R_(2))/(R_(2)+10)…(2)`
From `(1)` and `(2)` `R_(2)=5 Omega & R_(1)=10/3 Omega`
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