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In the circuit shown E, F, G and H are c...

In the circuit shown `E, F, G` and `H` are cells of emf `2V, 1V, 3V` and `1V` respectively and their internal resistance are `2Omega, 1Omega, 3Omega` and `1Omega` respectively.

A

`V_(D)-V_(B)=-2//13 V`

B

`V_(D)-V_(B)=2//13 V`

C

`V_(G)=21//13V`=potential difference across `G`

D

`V_(H)=19//13V`=potential difference across `H`

Text Solution

Verified by Experts

The correct Answer is:
A, C, D

In loop `DCBD implies 3-3I-1-I-2(I-I_(1))=0`
`3I-I_(1)=1…(1)`
In loop `DCBAB`
`4I+3I_(1)=3…..(2)`
From `(1)` and `(2)`
`I=6/13 Amp,I_(1)=5/13 Amp,I_(2)=1/13 Amp`
`V_(B)-V_(D)=2xx1/13`
`V_(B)-V_(D)=2xx1/13`
`V_(B)-V_(D)=2/13` volt `implies V_(D)-V_(B)=-2/13` volt
`V_(G)=3-3I=3-3xx6/13 impliesV_(G)=21/13` volt
`V_(H)=1+Ixx1=1+6/13=19/13` volt
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