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Consider the circuit shown in the figure...

Consider the circuit shown in the figure

A

the current in the `5 Omega` resistor is `2A`

B

the current in the `5 Omega`resistor is `1A`

C

the potential difference `V_(A)-V_(B)` is `10 V`

D

the potential difference `V_(A)-V_(B)` is `5V`

Text Solution

Verified by Experts

The correct Answer is:
A
`R_(eq)=14 Omega`
`I=28/14 =2 Amp`
`V_(A)+3xx1-10xx1=V_(B)`
`V_(A)-V_(B)=7` volt
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