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Consider the circuit shown in the figure...

Consider the circuit shown in the figure

A

the current in the `5 Omega` resistor is `2A`

B

the current in the `5 Omega`resistor is `1A`

C

the potential difference `V_(A)-V_(B)` is `10 V`

D

the potential difference `V_(A)-V_(B)` is `5V`

Text Solution

Verified by Experts

The correct Answer is:
A
`R_(eq)=14 Omega`
`I=28/14 =2 Amp`
`V_(A)+3xx1-10xx1=V_(B)`
`V_(A)-V_(B)=7` volt
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Knowledge Check

  • For the circuit shown in the figure :

    A
    Current through Zener diode is 4 mA
    B
    Current through Zener diode is 9 mA
    C
    The output voltage is 60 V
    D
    The output voltage is 40 V

  • For the circuit shown in the figure:

    A
    current through zener diode is 4 mA.
    B
    current through zener diode is 9 mA
    C
    the output voltage is 50 V
    D
    the output voltage is 40 V

  • In the circuit shown in the figure .

    A
    current passing through `2Omega` resistance is zero.
    B
    current passing through `4Omega` resistance is `5A`
    C
    current passing through `5Omega` resistance is 4A.
    D
    potential difference across `2Omega` resistance is zero.

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