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In a potentiometer wire experiment the e...

In a potentiometer wire experiment the emf of a battery in the primary circuit is `20V` and its internal resistance is `5Omega`. There is a resistance box in series with the battery and the potentiometer wire, whose resistance can be varied from `120Omega` to `170Omega`. Resistance of the potentiometer wire is `75Omega`. The following potential differences can be measured using this potentiometer.

A

`5 V`

B

`6V`

C

`7V`

D

`8V`

Text Solution

Verified by Experts

The correct Answer is:
A, B, C
Maximum potential difference that can be measured `=20/((5+120+75))xx75=7.5` volt.
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