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Find the current (in mA) in the wire bet...

Find the current (in `mA`) in the wire between point `A` and `B`.

Text Solution

Verified by Experts

The correct Answer is:
`0007.50`
`R_(eq)=(1 k Omega||2 k Omega)+(1 K Omega||2 K Omega)`
`R_(eq)=2/3K Omega+2/3 K Omega=4/3 K Omega`

`I=30/(R_(eq))=45/2 mA`
`I_(1)=1/3xx45/2=15/2 mA& I_(2)=2/3xx45/2=15 mA`
So, `I_(AB)=I_(2)-I_(1)=15/2 mA`
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