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In the primary circuit of potentiometer ...

In the primary circuit of potentiometer the rheostat can be varied from `0` to `10Omega`. Initially it is at minimum resistance (zero).

(a) Find the length `AP` of the wire such that the galvanometer shows zero deflection.
(b) Now the rheostat is put at maximum resistance `(10Omega)` and the switch `S` is closed. New balancing length is found to `8m`. Find the internal resistance `r` of the `4.5V` cell.

Text Solution

Verified by Experts

The correct Answer is:
`(a) 6m, (b) 1 Omega`
(a) `4.5=10/(9+1)xx9/12xxl=3/4xxlimplies l=6m`
(b) `V=10/(1+10+9)xx9/12xx8`
`4.5/(r+2)xx2=1/3xx9/12xx8`
`9/(r+2)=(9xx8)/(2xx12) impliesr =1Omega`
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