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The resistance of the series combination...

The resistance of the series combination of two resistances is S. When they are joined in parallel the total resistance is P. If S= nP then the minimum possible value of n is

A

`4`

B

`3`

C

`2`

D

`1`

Text Solution

Verified by Experts

The correct Answer is:
A
`R_(1)+R_(2)=S, (R_(1)R_(2))/(R_(1)+R_(2))=P`
`s=npimplies(R_(1)+R_(2))^(2)=nR_(1)R_(2)`
`implies n=((R_(1))/(R_(2))+(R_(2))/(R_(1))+2)`
`impliesn_(min)=2+2=4`
`:. (x+1/x)_(min)=2` for `xgt0`
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