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The resistance of a bulb filmanet is 100...

The resistance of a bulb filmanet is `100Omega` at a temperature of `100^@C`. If its temperature coefficient of resistance be 0.005 per `.^@C`, its resistance will become `200 Omega` at a temperature of

A

`200^(@)C`

B

`300^(@)C`

C

`400^(@)C`

D

`500^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
B
Let resistance of bulb filament is `R_(0)` at `0^(@)C`, then from expression
`R=R_(0)(1+alphaDeltaT)`
`:. 100=R_(0)(1+0.005xx100)`
`200=R_(0)(1+0.005xxx)`
Where `x` is temperature in `.^(@)C` at which resistance becomes `200 Omega`
Dividing the above two equation
`200/100=(1+0.005 x)/(1+0.005xx100)implies x=400^(@)C`
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