Consider a cylinderical element as shown in the figure. Currents flowing the through elements is `I` and resistivity of material of the cylinder is `rho`. Choose the correct options out the following

Options

A. Power loss in second half is four times the power loss in first hafl
B. Voltage drop in fist half is twice of voltage drop in second half
C. current density in both halves are equal
D. electric field in both halves is equal

Answer

A

Explanation

`R_(1)=rho(l//2)/(pi(4r)^(2))impliesR_(1)=1/32 l/(pil^(2))`
`R_(2)=rho(l//2)/(pi(2r)^(2))impliesR_(2)=1/8 l/(pil^(2))`
`R_(2)=4R_(1)`