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A resistance of 2 Omega is connected acr...

A resistance of `2 Omega` is connected across one gap of a meter bridge (the length of the wire is `100 cm` and an unknown resistance, greater than ` 2 Omega`, is connected across the other gap. When these resistance are interchanged, the balance point shifts by `20cm`. Neglecting any corrections, the unknown resistance is.
(a)` 3 Omega`
(b) `4 Omega`
( c) `5 Omega`
(d) `6 Omega`.

A

`3 Omega`

B

`4 Omega`

C

`5 Omega`

D

`6 Omega`

Text Solution

Verified by Experts

The correct Answer is:
A
`2/X=l/(100-l)...(1)`
When resistance are interchanged
(since `Xgt2 Omega`)
`X/2=(l+20)/(100-(l+20))impliesX/2=(l+20)/(80-l)...(2)`
From `(1)` and `(2) l=40cm`, and `X=3 Omega`
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