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A charge particle A of charge q=2C has v...

A charge particle `A` of charge `q=2C` has veocity `V=100m//s` When it passes through point `A` and has velocity in the direction shown. The strength of magnetic field at point `B` due to this moving charge is `(r =2m)`
.

A

`2.5 mu T`

B

`5.0 mu T`

C

`2.0 mu T`

D

None .

Text Solution

Verified by Experts

The correct Answer is:
A
`oversetrarr(B)=(mu_0)/(4pi) (q(oversetrarrVxxoversetrarrr))/(r^(3) ) = (mu_(0))/(4pi) = (qVsin0)/(r^(2))`
`= 10^(-7) xx (2 xx 100 xx sin 30^(@))/(2^(2))`
`=25 xx 10^(-7) T = 2.5 mu T` .
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