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An electron is projected with velocity v...

An electron is projected with velocity `v_(0)` in a unifrom electric field E perpendicular to the field Again it is projectced with velocity `v_(0)` perpendicular to a unifrom magnetic field `B//` if `r_(1)` is initial radius of curvature just after entering in the electric field and `r_(2)` is initial radius of curvature just after entering in magnetic field then the ratio `r_(1)//r_(2)` is equal to .

A

`(Bv_(0)^(2))/(E)`

B

`(B)/(E)`

C

`(Ev_(0))/(B)`

D

`(Bv_(0))/(B)`

Text Solution

Verified by Experts

The correct Answer is:
D
`eE = (mV_(0)^(2))/(r_(1)) implies r_(1) = (mV_(0)^(2))/(eE) `
`eV_(0)B = (mV_(0)^(2))/(r_(2)) = (mV_(0))/(eB) implies (r_(1))/(r_(2)) =(V_(0)B)/(E)` .
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