Home
Class 12
PHYSICS
An electron (mass =9.1xx10^(-31)kg, char...

An electron (mass `=9.1xx10^(-31)kg`, charge `=1.6xx10^(-19)C`) experiences no deflection if subjected to an electric field of `3.2x10^(5)V/m`, and a magnetic fields of `2.0xx10^(-3)Wb/m^(2)`. Both the fields are normal to the path of electron and to each other. If the electric field is removed, then the electron will revolve in an orbit of radius

A

`45m`

B

`4.5m`

C

`0.45m`

D

0.045m`

Text Solution

Verified by Experts

The correct Answer is:
C
`oversetrarr(F_(e)) + oversetrarr(F_(m)) = 0 implies F_(e) = F_(m)`
`eE = eVB`
`v = (E)/(B) implies (3.2 xx 10^(5))/(2 xx 10^(-3)) = 1.6 xx 10^(8) m//s`
`r =(mv)/(qB) = (9.1 xx 10^(-3) xx 1.6 xx 10^(8))/(1.6 xx 10^(-19) xx 2 xx 10^(-3)\) = 0.45 m` .
Promotional Banner

Similar Questions

Explore conceptually related problems

An electron (mass =9.1xx10^(-31)kg , charge =1.6xx10^(-19)C ) experiences no deflection if subjected to an electric field of 3.2 x 10^(5)V/m , and a magnetic fields of 2.0xx10^(-3)Wb/m^(2) . Both the fields are normal to the path of electron and to each other. If the electric field is removed, then the electron will revolve in an orbit of radius

An electron (mass =9xx10^(-31)kg . Charge =1.6xx10^(-19)C) whose kinetic energy is 7.2xx10^(-18) joule is moving in a circular orbit in a magnetic field of 9xx10^(-5) "weber"//m . The radius of the orbit is

An electron (mass =9.0xx10^(-31) kg and charge =1.6xx10^(-19) coulomb) is moving in a circular orbit in a magnetic field of 1.0xx10^(-4)"weber"//m^(2) . Its perido of revolution is

An electron beam passes through a magnitic field of 2xx10^(-3) "weber"//m^(2) and an electric field of 1.0 xx 10^(4) "volt/m" both acting simultaneously. If the electric field is removed, what will be the radius of the electron path ?

A narrow electron beam passes undeviated through an electric field E = 3 xx 10^(4) "volt"//m and an overlapping magnetic field B = 2 xx 10^(-3) Weber//m^(2) . If electric field and magnetic field are mutually perpendicular. The speed of the electron is

An electron beam passes through a magnetic field of 2xx10^-3 weber//m^2 and an electric field of 1*0xx10^4Vm^-1 both acting simultaneously. The path of electrons remaining undeviated, calculate the speed of the electrons. If the electric field is removed what will be the radius of the electron path?

An electron beam passes through a magnetic field of 4xx10^-3 weber//m^2 and an electric field of 2xx10^4Vm^-1 , both acting simultaneously. The path of electron remaining undeviated, calcualte the speed of the electrons. If the electric field is removed, what will be the radius of the electron path?