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Two long conductors, separated by a dist...

Two long conductors, separated by a distance `d` carry current `I_(1) and I_(2)` in the same direction . They exert a force `F` on each other. Now the current in one of them is increased to two times and its direction is reversed . The distance is also increased to `3d`. The new value of the force between them is

A

`-2F`

B

`(F)/(3)`

C

`(-2F)/(3)`

D

`(-F)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
1
Force acting between two current carrying conductors
`F = (mu_(0))/(2pi) (|_(1)|_(2))/(d) `
where d =distnace between the conductors 1=length of each conductor
Again `%F' = (mu_(0))/(2pi) ((-2|_(1))(|_(2)))/((3d) )1`
Thus from equations (i) and (ii)
`(F')/(F) =(2)/(3) implies F' =(2)/(3)F` .
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