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A charged particle of mass m and charge ...

A charged particle of mass `m` and charge `q` travels on a circular path of radius `r` that is perpendicular to a magnetic field `B`. The time takeen by the particle to complete one revolution is

A

`(2piqB)/(m)`

B

`(2pim)/(qB)`

C

`(2pimq)/(B)`

D

`(2pimq)/(B)`

Text Solution

Verified by Experts

The correct Answer is:
4
Magnetic force `F =quB..(i)`
Centripetal force
`F = (m upsilon^(2))/R`
From Eq (i) and (ii)
`(m upsilon^(2))/R = q upsilon B implies r = (m upsilon )/(qB)`
The Time taken by the particle to complete one revolution
` T = (2pir)/(upsilon) = (2pi m upsilon)/(qB) = (2pim)/(qB)` .
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