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Two particles A and B of masses m(A) an...

Two particles `A and B` of masses ` m_(A) and m_(B)` respectively and having the same charge are moving in a plane . The speeds of the particles are ` v_(A) and v_(B)` respectively and the trajectories are as shown in the figure. Then

A

`m_(A)V_(A) ltm_(B)V_(B)`

B

`m_(A)V_(A) gt m_(B)V_(B)`

C

`m_(A) lt m_(B) ` and `V_(A) lt V_(B)`

D

`m_(A) = m_(B) ` and `V_(A) = V_(B)`

Text Solution

Verified by Experts

The correct Answer is:
`B`
`r = (mv)/(qB)` Givent that `r_(A) gt r_(B)`
`m_(A) V_(A) gtm_(V) V_(B)` .
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