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A square wire loop of 10.0 cm side lies ...

A square wire loop of `10.0 cm` side lies at right angles to a uniform magnetic field of `20T`. A `10 V` light bulb is in a series with the loop as shown in the fig. The magnetic field is decreasing steadily to zero over a time interval `Deltat`. The bulb will full brightness if `Deltat` is equal to

A

`20 ms`

B

`0.02 ms`

C

`2 ms`

D

`0.2 ms`

Text Solution

Verified by Experts

The correct Answer is:
A
`e= -(Deltaphi)/(Deltat)=(phi_(i)-phi_(f))/(Deltat)`
`deltat=(phi_(i)-phi_(f))/e=(BA-0)/e=(20xx10^(-2))/10`
`=20xx10^(-3) sec =20 ms`
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