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A closed planer wire loop of area A and ...

A closed planer wire loop of area `A` and arbitrary shape is placed in a uniforms magnetic field of magnitude `B`, with iits plane perpendicualr to magnetic field. The resistance of the wire loop is `R`. The loop is now turned upside down by `180^(@)` so that its plane again becomes perpendicular to the magentic field. The total charge that must have flowed through the wire ring in the process is

A

`lt AB//R`

B

`= AB//R`

C

`= 2AB//R`

D

None

Text Solution

Verified by Experts

The correct Answer is:
C
`Deltaq=N/R(phi_(1)-phi_(2))=(2BA)/R`
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