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A cionducing rod moves with constant vel...

A cionducing rod moves with constant velocity `v` perpendicular to the straight wire carrying a current I as shown compute that the emf generated between the ends of the rod

A

`(mu_(0)vIl)/(pir)`

B

`(mu_(0)vIl)/(2pir)`

C

`(2mu_(0)vIl)/(pir)`

D

`(mu_(0)vIl)/(4pir)`

Text Solution

Verified by Experts

The correct Answer is:
B
`e=Blv=mu_(0)/(4pi)(2I)/rlv`
`e=(mu_(0)Ilv)/(2pir)`
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