A metallic rod length `L` and the mass `M` is moving under the action of two unequal `F_(1)` and `F_(2)` (directed opposite to each other) acting at its ends along its length. Ignore gravity and any external magnetic field. If sepecific charge of electrons is `(e//m)`, then the potential difference between the ends of the rod is steady state must be

Options

A. `|F_(1)-F_(2)|mL//eM`
B. `(F_(1)-F_(2))mL//eM`
C. `[mL//eM] [F_(1)//F_(2)]`
D. None

Answer

A

Explanation

`(m(F_(1)-F_(2)))/M=eE`
`(m(F_(1)-F_(2)))/(Me)`
`V=EL=(m(F_(1)-F_(2)))/(Me)L`