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The magnetic field in a region is given ...

The magnetic field in a region is given by `vec(B)=B_(0)(1+(x)/(a))hat(k)`. A square loop of edge length 'd' is placed with its edge along X-axis and Y-axis. The loop is moved with a constant velocity `vec(V)=V_(0)hat(i)`. The emf induced in the loop is

A

`(V_(0)B_(0)d^(2))/a`

B

`(V_(0)B_(0)d^(2))/(2a)`

C

`(V_(0)B_(0)a^(2))/d`

D

None

Text Solution

Verified by Experts

The correct Answer is:
A
`phi=BA=B_(0)(1+x/a)d^(2)=B_(0)d^(2)+(B_(0)d^(2))/ax`
`(dphi)/(dt)=(B_(0)d^(2))/a(dx)/(dt) implies e=(B_(0)d^(2)V_(0))/a`
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