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A ring of resistance 10Omega, radius 10 ...

A ring of resistance `10Omega`, radius `10 cm` and `100` turns is rotated at a rate revolutions per second about its diameter is perpendicular to a uniform magnetic field of induction `10 mT`. The amplitude of the current in the loop will be nearly `("Take": pi^(2)=10)`

A

`200A`

B

`2A`

C

`0.002A`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
`phi=NAB cos omegat`
`e=NBAomega sinomegat`
`e_(0)=NBAomega`
`I_(0)=(NBAomega)/R`
`=(100xx10^(-2)xxpixx(.1)^(2)2pixx100)/10=2A`
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