Home
Class 12
PHYSICS
For L-R circuit, the time constant is eq...

For L-R circuit, the time constant is equal to

A

twice the ratio of the energy strored in the magnetic field to the rate of dissipation of energy in the resistance

B

ratio of the energy stored in the magnetic field to the rate of dissipation of energy in the resistance

C

half the ratio of the energy stored in the magnetic field to the rate of dissipation of energy in the resistance

D

square of the ratio of the energy stored in the magnetic field to the rate of dissipation of energy in the resistance

Text Solution

Verified by Experts

The correct Answer is:
A
`tau=L/R=(2xx1/2LI^(2))/(I^(2)R)`
Promotional Banner

Similar Questions

Explore conceptually related problems

During current growth in an L-R circuit the time constant is the time in which the magnitude of current becomes

The figure shows an L-R circuit the time constant for the circuit is

The growth of current in an L-R circuit in time t=L/r is equal to about __

A current i_(0) is flowing through an L-R circuit of time constant i_(0) . The source of the current is switched off at time t = 0 . Let r be the value of (-di//dt) at time t = 0 .Assuming this rate to be constant, the current will reduce to zero in a time interval of

In a parallel L-C-R circuit spring constant K is analogous to :-

In the transient circuit shown the time constant of the circuit is -

The time constant of C-R circuit is

Given L_(1) = 1 mH , R_(1) = 1 Omega , L_(2) = 2 mH , R_(2) = 2 Omega Neglecting mutual inductanec, the time constants (in ms) for circuits (i), (ii), and (iii) are

If for above circuit the capacitive reactance is two times of inductive Reactance, and resistance R is equal to inductance Reactance then power factor of circuit is .