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A current of 2 A is increasing at a rate...

A current of `2 A` is increasing at a rate of `4 A s^(-1)` through a coil of inductance `1 H`. Find the energy stored in the inductor per unit time in the units of `J s^(-1)`.

A

`2 J//s`

B

`1 J//s`

C

`16 J//s`

D

`4 J//s`

Text Solution

Verified by Experts

The correct Answer is:
C
`P=ei=L(di)/(dt)xxi=2xx4xx2`
`P=16 J//sec`
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