Home
Class 12
PHYSICS
In the circuit (Fig.) what is potential ...

In the circuit (Fig.) what is potential difference `V_(B) - V_(A)` (in `V`) when current `I` is `5 A` and is decreasing at the rate of `10^(3) A s^(-1)`

A

`15 V`

B

`10 V`

C

`-15 V`

D

`20 V`

Text Solution

Verified by Experts

The correct Answer is:
C
Since current is decreasing so induce emf will support main current.

`V_(A)-IR-15-L(dI)/(dt)=V_(B)`
`V_(B)-V_(A)=-IR-15-L(dI)/(dt)=-5xx1-15-5xx10^(-3)xx(-10^(-3))=15` volt
Promotional Banner

Similar Questions

Explore conceptually related problems

What is the potential difference V_(B)-V_(A) when the current i is 5A and is decreasing at a rate of 10^(3) A /s

In the circuit shown, what is the potential difference V_(PQ) ?

The network shown in Fig. is a part of a complete circuit.What is the potential difference V_(B)-V_(A) when the current I is 5A and is decreasing at a rate of 10^(2)(A//s) ?

In the circuit shown , what is the potential difference V_(PQ) ?

The network shown in the figure is a part of complete circuit. What is the potential difference V_B-V_A when the current I is 5 A and is decreasing at a rate of 10^3A//s ?

In the circuit shown, what is the potential different V_(PQ) ?

Potential difference V_(A) - V_(B) in the network shown in

Potential difference V_(B)-V_(A) in the network shown is

In the given circuit, current I is 2A and it is decreasing at the rate of 10^3 AS^(-1) .Then V_B- V_A is

AB is a part of circuit. Find the potential difference V_(A) - V_(B) if a. current I = 2 A and is constant, b. current i = 2 A and is increasing at the rate of 1 A s^(-1) , c. current i = 2 A and is decreasing at the rate 1 A s^(-1) ,