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The phase difference between the voltage...

The phase difference between the voltage and the current in an AC circuit is `pi//4`. If the frequency is `50Hz` then this phase difference will be equivalent to a time of

A

`0.78 s`

B

`15.7 ms`

C

`0.25 s`

D

`2.5 ms`

Text Solution

Verified by Experts

The correct Answer is:
D
`(Deltaphi)/(2pi)=(Deltat)/Timplies (Deltaphi)/(2pi)=(Deltat)/(2pi//omega)`
`implies Deltat=(Deltaphi)/omega`
`Deltat=pi/(4xx100pi)=1/400=2.5xx10^(-3) sec=2.5 ms`
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