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In series LR circuit, X(L) = 3 R. Now a ...

In series `LR` circuit, `X_(L) = 3 R`. Now a capacitor with `X_(C ) = R` is added in series. The ratio of new to old power factor

A

`1`

B

`2`

C

`1/sqrt(2)`

D

`sqrt(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`cos phi_(1)=R/sqrt(R^(2)+X_(L)^(2))=R/sqrt(R^(2)+(3R)^(2))=1/sqrt(10)`
`cos phi_(2)=R/sqrt(R^(2)+(X_(L)-X_(C ))^(2))=R/(R^(2)+(2R)^(2))=1/sqrt(5)`
`(cos phi_(2))/(cos phi_(1))=sqrt(2)/1`
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