Home
Class 12
PHYSICS
The adjoining figure shows two bulbs B(1...

The adjoining figure shows two bulbs `B_(1)` and `B_(2)` resistor `R` and an inductor and `L`. When the switch `S` is turned off

A

The bulb `B_(2)` lights up earlier than `B_(1)` and finally both the bulbs shine equally bright.

B

`B_(1)` light up earlier and finally both the bulbs acquire equal brightness.

C

`C_(2)` lights up earlier and finally `B_(1)` shines brighter than `B_(2)`.

D

`B_(1)` and `B_(2)` light up togather with equal brightness all the time.

Text Solution

Verified by Experts

The correct Answer is:
A

Due to induction effect inductor delay the growth of current.
Promotional Banner

Similar Questions

Explore conceptually related problems

Figure represents two bullbs B_(1)" and " B_(2) resister R and inductor L. When the switch S in turned off,then

In the circuit shown in figure, if both the bulbs B_(1) and B_(2) are identical:

The adjoining figure shows an AC circuit with resistane R , inductance L and source voltage V_S . Then

In the given figure switches S_(1) and S_(2) are in open condition. The resistance across ab when the switches S_(1) and S_(2) are closed is ……………… Omega .

An inductor L, a resistanc eR and two identical bulbs B_(1) and B_(2) are connected to a battery through a switch S as shown in the figure . The resistance of coil having inductance L is also R. Which of the following statement gives the corrrect description of the happenings when the switch S is closed?

Three bulbs A, B, C are connected in a circuit as shown in Figure 14.2. When the switch is ‘ON’