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The horizontal component of the earth's ...

The horizontal component of the earth's magnetic field at a place is `3.0 X 10^(-4) T` and the dip is `53^@`. A metal rod of length 25cm is placed in the north - south direction and is moved at a constant speed of 10cm s^(-1) towards east. Calculate the emf induced in the rod.

Text Solution

Verified by Experts

The correct Answer is:
`10 muV`

`e=B_(V)lV`
`e=B_(H)tantheta.lV`
`=3xx10^(-4)xx4/3xx0.25xx0.1`
`=10^(-5)` volt= 1 muV
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