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A wire forming one cycle of sine curve i...

A wire forming one cycle of sine curve is moved in x-y plane with velocity `vec(V)=V_(x)hat(i)+V_(y)hat(j)`. There exist a magnetic field `vec(B)=-B_(0)hat(k)`.
Find the motional emf decelop across the ends PQ of wire.

Text Solution

Verified by Experts

The correct Answer is:
`lambdaV_(y)B_(0)`
`e=-(vec(B)xxvec(V)).vec(l)=-[B_(0)hat(k)xx(V_(x)hat(i)+V_(y)hat(j)].lambdahat(i)=B_(0)V_(y)lambda`
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