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A horizontal wire is free to slide on th...

A horizontal wire is free to slide on the verticle rails of a conducting frame as shown in figure. The wire has a mass `m` and length `l` and the resistance of the circuit is `R`. If a uniform magnetic field `B` is directed perpendicular to the frame, the terminal speed of the wire as it falls under the force of gravity is

Text Solution

Verified by Experts

The correct Answer is:
`(mgR)/(B^(2)l^(2))`
`mg=IlB implies mg=e/RlB`
`m mg=(Blv)/RlB implies v=(mgR)/(B^(2)l^(2))`
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