A triangular wire frame (each side =2m) is placed in a region of time variant magnetic field `dB//dt = (sqrt3) T//s`. The magnetic field is perpendicular to the plane of the triangle and its centre coincides with the centre of triangle. The base of the triangle AB has a resistance `1(Omega)` while the other two sides have resistance `2(Omega)` each. The magnitude of potential difference between the points A and B will be

Answer

`0.4 V`

Explanation

`phi=BA implies (dphi)/(dt)=A(dB)/(dt)`
`e=1/2xx2xxsqrt(3)xxsqrt(3)=3` volt
`I=3/5 Amp implies V_(AB)=1-3/5xx10.4` volt