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An e.m.f. of 15 volt is applied in a cir...

An e.m.f. of `15` volt is applied in a circuit containing `5` henry inductance and `10` ohm resistance. The ratio of the current at time `t=oo` and at `t=1` second is

Text Solution

Verified by Experts

The correct Answer is:
`e^(2)/(e^(2)-1)`

`tau=L/R=5/10=1/2`
`I_(t=oo)=I_(0)=15/10=3/2 amp`
`I=I_(0)(1-e^(-t//tau))=I_(0)(1-e^(-2))=I_(0)(1-1/e^(2))`
`I/I_(0)=(e^(2)-1)/e^(2)`
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